1916 United States presidential election in Delaware

The 1916 United States presidential election in Delaware took place on November 7, 1916. All 48 contemporary states participated in the 1916 United States presidential election. Voters chose three electors to the Electoral College, which selected the president and vice president.

1916 United States presidential election in Delaware

← 1912 November 7, 1916 1920 →
 
Nominee Charles Evans Hughes Woodrow Wilson
Party Republican Democratic
Home state New York New Jersey
Running mate Charles W. Fairbanks Thomas R. Marshall
Electoral vote 3 0
Popular vote 26,011 24,753
Percentage 50.20% 47.78%

County Results

President before election

Woodrow Wilson
Democratic

Elected President

Woodrow Wilson
Democratic

Republican nominee and Supreme Court justice Charles Evans Hughes carried Delaware with 50.20% of the vote, defeating Democratic nominee and incumbent president Woodrow Wilson, who won 47.78% of the vote. This election marks one of three times in the 20th century that the state voted for the losing candidate, along with 1932 and 1948.

Wilson was the first Democrat to win the presidency without Delaware since James K. Polk in 1844, and Hughes the first Republican to ever carry Delaware without winning the presidency.

Results

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1916 United States presidential election in Delaware[1]
Party Candidate Votes Percentage Electoral votes
Republican Charles Evans Hughes 26,011 50.20% 3
Democratic Woodrow Wilson (inc.) 24,753 47.78% 0
Prohibition Frank Hanly 566 1.09% 0
Socialist Allan L. Benson 480 0.93% 0
Totals 51,810 100.0% 3

See also

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References

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  1. ^ "1916 Presidential General Election Results - Delaware". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved November 22, 2020.