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1887 Iowa gubernatorial election

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1887 Iowa gubernatorial election

← 1885 November 8, 1887 1889 →
 
Nominee William Larrabee Thomas J. Anderson
Party Republican Democratic
Popular vote 169,596 153,706
Percentage 50.18% 45.47%

County results
Larrabee:      40-50%      50-60%      60-70%      70-80%      80-90%
Anderson:      40-50%      50-60%      60-70%      70-80%

Governor before election

William Larrabee
Republican

Elected Governor

William Larrabee
Republican

The 1887 Iowa gubernatorial election was held on Tuesday November 8, 1887. Incumbent Republican William Larrabee defeated Democratic nominee Thomas J. Anderson with 50.18% of the vote.

General election

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Candidates

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Major party candidates

  • William Larrabee, Republican
  • Thomas J. Anderson, Democratic

Other candidates

  • M. J. Cain, Union Labor
  • V. G. Farnham, Prohibition

Results

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1887 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican William Larrabee (incumbent) 169,596 50.18%
Democratic Thomas J. Anderson 153,706 45.47%
Labor M. J. Cain 14,283 4.23%
Prohibition V. G. Farnham 334 0.10%
Majority 15,890
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 14, 2020.