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Revision History for A326725

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Showing entries 1-10 | older changes
a(n) = (1/2)*n*(5*n - 7); row 5 of A326728.
(history; published version)
#13 by Michael De Vlieger at Tue Dec 24 22:12:30 EST 2024
STATUS

reviewed

approved

#12 by Andrew Howroyd at Tue Dec 24 16:26:58 EST 2024
STATUS

proposed

reviewed

#11 by Elmo R. Oliveira at Tue Dec 24 09:33:02 EST 2024
STATUS

editing

proposed

#10 by Elmo R. Oliveira at Tue Dec 24 09:32:10 EST 2024
FORMULA

G.f.: -x*(1 - 6*x) / (1 - x)^3.

a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) for n > 2. (End)

(End)

E.g.f.: exp(x)*x*(5*x - 2)/2. - Elmo R. Oliveira, Dec 24 2024

STATUS

approved

editing

#9 by Susanna Cuyler at Mon Aug 05 07:36:10 EDT 2019
STATUS

proposed

approved

#8 by Colin Barker at Mon Aug 05 05:17:31 EDT 2019
STATUS

editing

proposed

#7 by Colin Barker at Mon Aug 05 05:17:03 EDT 2019
LINKS

Colin Barker, <a href="/A326725/b326725.txt">Table of n, a(n) for n = 0..1000</a>

STATUS

approved

editing

#6 by Peter Luschny at Sun Aug 04 18:23:28 EDT 2019
STATUS

proposed

approved

#5 by Colin Barker at Sun Aug 04 12:15:41 EDT 2019
STATUS

editing

proposed

#4 by Colin Barker at Sun Aug 04 12:15:01 EDT 2019
LINKS

<a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (3,-3,1).

FORMULA

From Colin Barker, Aug 04 2019: (Start)

G.f.: -x*(1 - 6*x) / (1 - x)^3.

a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) for n>2.

(End)

PROG

(PARI) concat(0, Vec(-x*(1 - 6*x) / (1 - x)^3 + O(x^40))) \\ Colin Barker, Aug 04 2019

STATUS

proposed

editing