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LinearRecurrence[{3, 0, -3, 1}, {0, 2, 8, 23}, 30] (* Harvey P. Dale, Mar 30 2023 *)
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From _a(n) = (1/10)*((-1)^n - 15 + 2*Lucas(2*n+4)). - _G. C. Greubel_, Jan 21 2022: (Start)
a(n) = (1/10)*((-1)^n - 15 + 2*Lucas(2*n+4)).
a(n) = (1/10)*((-1)^n - 15 + 14*ChebyshevU(n, 3/2) - 6*ChebyshevU(n-1, 3/2)). (End)
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a(n) = (1/10)*((-1)^n - 15 + 2*LucasLLucas(2*n+4)).
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G. C. Greubel, <a href="/A180664/b180664.txt">Table of n, a(n) for n = 0..1000</a>
a(n+1) = Sum_{k=0..n} A180662(2*n-k+2, k+2).
a(n) = (-15 + (-1)^(-n) + (6-2*A)*A^(-n-1) + (6-2*B)*B^(-n-1))/10 with A=(3+sqrt(9-45))/2 and B=(3-sqrt(9-45))/2.
From G. C. Greubel, Jan 21 2022: (Start)
a(n) = (1/10)*((-1)^n - 15 + 2*LucasL(2*n+4)).
a(n) = (1/10)*((-1)^n - 15 + 14*ChebyshevU(n, 3/2) - 6*ChebyshevU(n-1, 3/2)). (End)
(Magma) [(1/10)*((-1)^n - 15 + 2*Lucas(2*n+4)): n in [0..40]]; // G. C. Greubel, Jan 21 2022
(Sage) [(1/10)*((-1)^n - 15 + 2*lucas_number2(2*n+4, 1, -1)) for n in (0..40)] # G. C. Greubel, Jan 21 2022
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