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Revision History for A074606

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Showing entries 1-10 | older changes
a(n) = 3^n + 5^n.
(history; published version)
#27 by Peter Luschny at Mon Jan 15 01:45:21 EST 2024
STATUS

reviewed

approved

#26 by Joerg Arndt at Mon Jan 15 00:49:20 EST 2024
STATUS

proposed

reviewed

#25 by G. C. Greubel at Sun Jan 14 23:44:29 EST 2024
STATUS

editing

proposed

#24 by G. C. Greubel at Sun Jan 14 23:44:20 EST 2024
LINKS

<a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (8,-15).

FORMULA

E.g.f.: e^exp(3*x) + e^exp(5*x). (End)

PROG

(SageMath) [3^n+5^n for n in range(41)] # G. C. Greubel, Jan 14 2024

STATUS

approved

editing

#23 by Charles R Greathouse IV at Thu Sep 08 08:45:07 EDT 2022
PROG

(MAGMAMagma) [3^n + 5^n: n in [0..35]]; // Vincenzo Librandi, Apr 30 2011

Discussion
Thu Sep 08
08:45
OEIS Server: https://oeis.org/edit/global/2944
#22 by R. J. Mathar at Thu Mar 10 06:06:40 EST 2022
STATUS

editing

approved

#21 by R. J. Mathar at Thu Mar 10 06:06:32 EST 2022
FORMULA

a(n) = 2*A081186(n). - R. J. Mathar, Mar 10 2022

STATUS

approved

editing

#20 by Susanna Cuyler at Sun Jan 14 18:27:44 EST 2018
STATUS

proposed

approved

#19 by Jon E. Schoenfield at Sun Jan 14 17:43:46 EST 2018
STATUS

editing

proposed

#18 by Jon E. Schoenfield at Sun Jan 14 17:43:43 EST 2018
NAME

a(n) = 3^n + 5^n.

FORMULA

From Mohammad K. Azarian, Jan 11 2009: (Start)

G.f.: 1/(1-3*x) + 1/(1-5*x). E.g.f.: e^(3*x)+e^(5*x). - _Mohammad K. Azarian_, Jan 11 2009

E.g.f.: e^(3*x) + e^(5*x). (End)

a(n) = 8*a(n-1) - 15*a(n-2) with a(0)=2, a(1)=8 . - Vincenzo Librandi, Jul 21 2010

PROG

(MAGMA) [3^n + 5^n: n in [0..35]]; // _Vincenzo Librandi, _, Apr 30 2011

STATUS

approved

editing