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A237428
Numbers k with following property: List all proper divisors of k. Replace any composite number in the list with its proper divisors. Repeat. Sum of remaining numbers (1's and primes) is equal to k.
0
6, 126, 3808, 19360, 104320, 4317184, 126764640
OFFSET
1,1
COMMENTS
Is there a largest term? Is there any odd term?
a(8) if it exists is greater than 10^9. - Giovanni Resta, Feb 07 2014
Numbers k such that k = A074206(k) + Sum_{p|k} (p-1)*A074206(k/p). - Charlie Neder, Jun 02 2019
EXAMPLE
6 is a term because: 1 + 2 + 3 = 6.
126 is a term because: [1 + 2 + 3 + (6 - 6) + 7 + (9 - 9) + (14 - 14) + (18 - 18) + (21 - 21) + (42 - 42) + (63 - 63)] + [1 + 2 + 3] + [1 + 3] + [1 + 2 + 7] + [1 + 2 + 3 + (6 - 6) + (9 - 9)] + [1 + 3 + 7] + [1 + 2 + 3 + (6 - 6) + 7 + (14 - 14) + (21 - 21)] + [1 + 3 + 7 + (9 - 9) + (21 - 21)] + [1 + 2 + 3] + [1 + 3] + [1 + 2 + 3] + [1 + 2 + 7] + [1 + 3 + 7] + [1 + 3] + [1 + 3 + 7] = 126.
MATHEMATICA
v[n_] := If[PrimeQ@n, 1, Block[{s = Sum[If[e == 1 || PrimeQ@e, e, v@e], {e, Most@ Divisors@n}]}, If[n < 1000, v[n] = s, s]]]; Select[Range@ 20000, # == v@# &] (* Giovanni Resta, Feb 07 2014 *)
CROSSREFS
KEYWORD
more,nonn
AUTHOR
Lechoslaw Ratajczak, Feb 07 2014
EXTENSIONS
a(6)-a(7) from Giovanni Resta, Feb 07 2014
STATUS
approved