{\displaystyle {\frac {N}{\sqrt {|p(x)|}}}\sin {\left({\frac {1}{\hbar }}\int _{x}^{a}|p(x)|dx-{\frac {\pi }{4}}\right)}\Longrightarrow -{\frac {N}{\sqrt {|p(x)|}}}\exp {\left({\frac {1}{\hbar }}\int _{a}^{x}|p(x)|dx\right)}}