{\displaystyle \mathrm {CH_{3}CH_{2}CH_{2}CH=CH_{2}+Br_{2}{\xrightarrow {}}CH_{3}CH_{2}CH_{2}CHBrCH_{2}Br{\xrightarrow[{\triangle }]{+K_{2}CO_{3}}}CH_{3}CH_{2}CH_{2}C\equiv CH+2KBr+H_{2}O+CO_{2}} }